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JEE Main 2021 (16 Mar, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2021 (16 Mar, Shift 2)

Q133JEE Main 2021 · 16 MAR · SHIFT 2Medium

Logic Gates

The following logic gate is equivalent to:

Figure

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Answer: (a)

  1. NAND with joined inputs is NOT, so the middle NAND receives Aˉ\bar{A} and Bˉ\bar{B}.
  2. Middle NAND: Aˉ Bˉ‾=A+B\overline{\bar{A}\,\bar{B}} = A + B.
  3. Last NAND (as NOT): Y=A+B‾Y = \overline{A + B}.
  4. So the answer is (a) NOR gate.
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