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MHT CET 2022 (11 Aug, Shift 2) · Energy Stored & Force between Plates

Energy Stored & Force between Plates question from MHT CET 2022 (11 Aug, Shift 2)

Q20MHT CET 2022 · 11 AUG · SHIFT 2Easy

Energy Stored & Force between Plates

The force between the plates of a parallel plate capacitor of capacitance 'CC' and distance of separation of the plates 'dd' with a potential difference 'VV' between the plates is

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Answer: (c)

  1. F=Q22ε0AF = \frac{Q^2}{2\varepsilon_0 A} and Q=CVQ = CV.
  2. Using ε0A=Cd\varepsilon_0 A = Cd: F=C2V22CdF = \frac{C^2V^2}{2Cd}
  3. F=CV22dF = \frac{CV^2}{2d}
  4. So the answer is (c) CV22d\frac{CV^2}{2d}.
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