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MHT CET 2025 (26 Apr, Shift 2) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from MHT CET 2025 (26 Apr, Shift 2)

Q12MHT CET 2025 · 26 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series

The frequencies for series limit of Balmer and Paschen series are ' $\nu_1$ ' and ' $\nu_3$ ' respectively. If frequency of first line of Balmer series ' $\nu_2$ ' then the relation between $\nu_1, \nu_2$ and $\nu_3$ is

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Answer: (c)

$\nu_1$ (Balmer limit) $= \frac{Rc}{4}$ ; $\nu_3$ (Paschen limit) $= \frac{Rc}{9}$ .
$\nu_2$ (Balmer first line, $3 \to 2$ ) $= Rc\left(\frac{1}{4} - \frac{1}{9}\right)$ .
$\nu_1 - \nu_2 = \frac{Rc}{9} = \nu_3$ (energy of level 3 to infinity).
So the answer is (c) $\nu_1 - \nu_2 = \nu_3$ .

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