The frequencies of three tuning forks A, B and C are related as nA > nB > nC. When the forks A and B are sounded together, the number of beats produced per second is ' n₁ '. When forks A and C are sounded together the number of beats produced per second is ' n₂ '. How may beats are produced per second when forks B and C are sounded together? (a) n₁ - n₂ (b) (n₁ + n₂)/(2) (c) n₂ - n₁ (d) n₁ + n₂

Answer: (c). nA - nB = n₁ and nA - nC = n₂. Subtract: nB - nC = n₂ - n₁. So the answer is (c) n₂ - n₁.

The frequencies of three tuning forks A, B and C are related as nA >… | MHT CET 2021 (20 Sep, Shift 1)

Q50MHT CET 2021 · 20 SEP · SHIFT 1Medium

Beats

The frequencies of three tuning forks $A, B$ and $C$ are related as $n_A > n_B > n_C$ . When the forks $A$ and $B$ are sounded together, the number of beats produced per second is ' $n_1$ '. When forks $A$ and $C$ are sounded together the number of beats produced per second is ' $n_2$ '. How may beats are produced per second when forks $B$ and $C$ are sounded together?

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Answer: (c)

$n_A - n_B = n_1$ and $n_A - n_C = n_2$ .
Subtract: $n_B - n_C = n_2 - n_1$ .
So the answer is (c) $n_2 - n_1$ .

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