Physics Circle home Student Login

Home›Chapters›Wave Optics PYQs›Wave Theory, Wavefronts & Doppler Effect›Question 24

NEET 2007 (AIPMT) · Wave Theory, Wavefronts & Doppler Effect

Wave Theory, Wavefronts & Doppler Effect question from NEET 2007 (AIPMT)

Q24NEET 2007 · AIPMTEasy

Wave Theory, Wavefronts & Doppler Effect

The frequency of a light wave in a material is 2 ×\times 1014 Hz and wavelength is 5000 A˚\mathring{A}. The refractive index of material will be

Show answer and solution

Answer: (b)

  1. Speed in the material: v=νλ=(2×1014)(5000×10−10)=1×108v = \nu\lambda = (2\times10^{14})(5000\times10^{-10}) = 1\times10^{8} m/s.
  2. Refractive index n=c/v=3×1081×108=3n = c/v = \dfrac{3\times10^{8}}{1\times10^{8}} = 3.
  3. So the answer is (b) 3.00.
Report a mistake

More questions on Wave Theory, Wavefronts & Doppler Effect