Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Spring Systems›Question 1

JEE Main 2026 (8 Apr, Shift 2) · Spring Systems

Spring Systems question from JEE Main 2026 (8 Apr, Shift 2)

Q1JEE Main 2026 · 8 APR · SHIFT 2Easy

Spring Systems

The frequency of oscillation of a mass mm suspended by a spring is v1v_1. If the length of the spring is cut to half, the same mass oscillates with frequency v2v_2. The value of v2/v1v_2/v_1 is ______.

Show answer and solution

Answer: (c)

  1. Half-length spring: k2=2k1k_2 = 2k_1.
  2. ν∝k⇒ν2ν1=2\nu \propto \sqrt{k} \Rightarrow \frac{\nu_2}{\nu_1} = \sqrt{2}.
  3. So the answer is (c) 2\sqrt{2}.
Report a mistake

More questions on Spring Systems