The frequency of revolution of an electron in the n th orbit of hydrogen atom is (a) directly proportional to n² (b) inversely proportional to n² (c) directly proportional to n³ (d) inversely proportional to n³

Answer: (d). f = (v)/(2π r) with v ∝ 1/n, r ∝ n². f ∝ (1/n)/(n²) = 1/n³ So the answer is (d) inversely proportional to n³.

The frequency of revolution of an electron in the n th orbit of… | MHT CET 2025 (19 Apr, Shift 2)

Q35MHT CET 2025 · 19 APR · SHIFT 2Easy

Bohr Model: Orbits, Speed & Angular Momentum

The frequency of revolution of an electron in the $n$ th orbit of hydrogen atom is

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Answer: (d)

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