Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Organ Pipes & Resonance Tube›Question 107

NEET 2018 · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from NEET 2018

Q107NEET 2018Medium

Organ Pipes & Resonance Tube

The fundamental frequency in an open organ pipe is equal to the third harmonic of a closed organ pipe. If the length of the closed organ pipe is 20 cm, the length of the open organ pipe is

Show answer and solution

Answer: (a)

  1. Open pipe fundamental v2Lo\frac{v}{2L_o} = closed pipe third harmonic 3v4Lc\frac{3v}{4L_c}.
  2. Lo=4Lc6=23×20=13.3L_o = \frac{4L_c}{6} = \frac{2}{3} \times 20 = 13.3 cm
  3. So the answer is (a) 13.2 cm (nearest option).
Report a mistake

More questions on Organ Pipes & Resonance Tube