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NEET 2015 (AIPMT, Cancelled Paper) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from NEET 2015 (AIPMT, Cancelled Paper)

Q113NEET 2015 · AIPMT · CANCELLED PAPERMedium

Organ Pipes & Resonance Tube

The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of organ pipe open at both the ends is

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Answer: (a)

  1. Closed pipe fundamental: v4×20\frac{v}{4 \times 20}; open pipe second overtone: 3v2Lo\frac{3v}{2L_o}.
  2. v80=3v2Lo⇒2Lo=240⇒Lo=120\frac{v}{80} = \frac{3v}{2L_o} \Rightarrow 2L_o = 240 \Rightarrow L_o = 120 cm
  3. So the answer is (a) 120 cm.
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