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MHT CET 2020 (19 Oct, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2020 (19 Oct, Shift 2)

Q98MHT CET 2020 · 19 OCT · SHIFT 2Medium

Organ Pipes & Resonance Tube

The fundamental frequency of a closed pipe is 400 Hz. If 13\frac{1}{3} rd pipe is filled with water, then the frequency of 2nd harmonic of the pipe will be (neglect and correction)

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Answer: (b)

  1. Closed pipe: n0=v4L=400n_0 = \frac{v}{4L} = 400 Hz.
  2. With 13\frac{1}{3} filled, air column =2L3= \frac{2L}{3}, new fundamental =400×32=600= 400 \times \frac{3}{2} = 600 Hz.
  3. A closed pipe gives only odd harmonics, so the next (second) note is the 3rd harmonic: 3×600=18003 \times 600 = 1800 Hz.
  4. So the answer is (b) 1800 Hz.
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