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MHT CET 2025 (25 Apr, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2025 (25 Apr, Shift 1)

Q42MHT CET 2025 · 25 APR · SHIFT 1Medium

Organ Pipes & Resonance Tube

The fundamental frequency of a closed pipe is 400 Hz. If $\left(\frac{1}{3}\right)$ rd length of the pipe is filled with water, the frequency of the $2$ nd harmonic of the pipe will be (Neglect end correction)

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Answer: (d)

Closed pipe: $n_0 = \frac{v}{4L} = 400$ Hz.
With $\frac{1}{3}$ filled, air column $= \frac{2L}{3}$ , new fundamental $= 400 \times \frac{3}{2} = 600$ Hz.
A closed pipe gives only odd harmonics, so the next (second) note is the 3rd harmonic: $3 \times 600 = 1800$ Hz.
So the answer is (d) 1800 Hz.

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