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MHT CET 2021 (23 Sep, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2021 (23 Sep, Shift 1)

Q86MHT CET 2021 · 23 SEP · SHIFT 1Medium

Organ Pipes & Resonance Tube

The fundamental frequency of an air column in pipe 'A' closed at one end coincides with second overtone of pipe 'B' open at both ends. The ratio of length of pipe 'A' to that of pipe 'B' is

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Answer: (c)

Pipe A (closed) fundamental: $\frac{v}{4L_A}$ ; pipe B (open) second overtone: $\frac{3v}{2L_B}$ .
$\frac{v}{4L_A} = \frac{3v}{2L_B} \Rightarrow L_A : L_B = 2 : 12 = 1 : 6$
So the answer is (c) $1:6$ .

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