The fundamental frequency of vibration of a string stretched between two rigid supports is 50 Hz. The mass of the string is 18 g and its linear mass density is 20 g/m. The speed of the transverse waves so produced in the string is ___________ m s⁻¹ Numerical answer type. Work it out, then open the answer.

Answer: 90. Length L = m/μ = 18/20 = 0.9 m. Fundamental: n = v/2L ⇒ v = 2Ln = 2×0.9×50 v = 90 m/s

The fundamental frequency of vibration of a string stretched between… | JEE Main 2023 (15 Apr, Shift 1)

Q64JEE Main 2023 · 15 APR · SHIFT 1Medium

Stationary Waves & Vibrating Strings

The fundamental frequency of vibration of a string stretched between two rigid supports is $50\text{ Hz}$ . The mass of the string is $18\text{ g}$ and its linear mass density is $20\text{ g/m}$ . The speed of the transverse waves so produced in the string is ___________ $\text{m s}^{-1}$

Numerical answer type. Work it out, then open the answer.

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Answer: 90

Length $L = \dfrac{m}{\mu} = \dfrac{18}{20} = 0.9\text{ m}$ .
Fundamental: $n = \dfrac{v}{2L} \Rightarrow v = 2Ln = 2\times0.9\times50$
$v = 90\text{ m/s}$

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