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MHT CET 2026 (15 May, Shift 1) · Gas Laws & Ideal Gas Equation

Gas Laws & Ideal Gas Equation question from MHT CET 2026 (15 May, Shift 1)

Q6MHT CET 2026 · 15 MAY · SHIFT 1Medium

Gas Laws & Ideal Gas Equation

The gas in a vessel is subjected to a pressure of $20$ atm. at $27^\circ$ C. Now half of the gas is released from the vessel and the temperature is raised by $50^\circ$ C. The pressure of a gas in a vessel is nearly

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Answer: (c)

Fixed volume: $P = \dfrac{nRT}{V} \Rightarrow \dfrac{P_2}{P_1} = \dfrac{n_2}{n_1}\cdot\dfrac{T_2}{T_1}$ .
$n_2 = \dfrac{n_1}{2}$ , $T_1 = 300$ K, $T_2 = 350$ K.
$P_2 = 20 \times \dfrac{1}{2} \times \dfrac{350}{300} = 11.67 \approx 12$ atm
So the answer is (c) $12$ atm.

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