The gases carbon-monoxide (CO) and nitrogen at the same temperature have kinetic energies E₁ and E₂ respectively. Then (a) E₁ = E₂ (b) E₁ > E₂ (c) E₁ < E₂ (d) E₁ and E₂ cannot be compared

Answer: (a). Average KE per molecule depends only on T and degrees of freedom: E = f/2kBT. CO and N ₂ are both diatomic ( f = 5) and at the same T. So the answer is (a) E₁ = E₂.

The gases carbon-monoxide (CO) and nitrogen at the same temperature… | NEET 2000 (AIPMT)

Q83NEET 2000 · AIPMTEasy

Gas Laws & Ideal Gas Equation

The gases carbon-monoxide (CO) and nitrogen at the same temperature have kinetic energies $E_1$ and $E_2$ respectively. Then

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Answer: (a)

Average KE per molecule depends only on $T$ and degrees of freedom: $E = \dfrac{f}{2}k_BT$ .
CO and N $_2$ are both diatomic ( $f = 5$ ) and at the same $T$ .
So the answer is (a) $E_1 = E_2$ .

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