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NEET 2024 · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from NEET 2024

Q33NEET 2024Medium

Wheatstone Bridge & Metre Bridge

The given circuit shows a uniform straight wire $AB$ of $40\text{ cm}$ length fixed at both ends. In order to get zero reading in the galvanometer $G$ , the free end of $J$ is to be placed from $B$ at:

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Answer: (d)

Balance: $\dfrac{8}{12} = \dfrac{AJ}{JB}$ with $AJ + JB = 40\text{ cm}$ .
$AJ = \dfrac{2}{5} \times 40 = 16\text{ cm}$ , so $JB = 24\text{ cm}$ .
So the answer is (d) 24 cm.

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