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JEE Main 2023 (25 Jan, Shift 2) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from JEE Main 2023 (25 Jan, Shift 2)

Q35JEE Main 2023 · 25 JAN · SHIFT 2Medium

Thermometry & Thermal Expansion

The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by :-

Figure

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Answer: (d)

  1. From the graph, P runs from 3030 (lower point, since 180−150=30180-150=30) to 180180; Q runs from 00 to 100100.
  2. tQ−0100=tP−30150\frac{t_Q-0}{100}=\frac{t_P-30}{150}
  3. So the answer is (d).
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