The graph of kinetic energy against the frequency v of incident light is as shown in the figure. The slope of the graph and intercept on X -axis respectively are (a) maximum KE threshold frequency (b) Planck's constant, threshold frequency (c) Planck's constant, work function (d) work function, maximum KE

Answer: (b). Einstein's equation: KE = hν - φ₀, a straight line y = mx + c. Slope = h (Planck's constant). At KE = 0: ν = φ₀/h = ν₀, the threshold frequency. So the answer is (b) Planck's constant, threshold frequency.

The graph of kinetic energy against the frequency v of incident light… | MHT CET 2020 (16 Oct, Shift 2)

Q56MHT CET 2020 · 16 OCT · SHIFT 2Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

The graph of kinetic energy against the frequency $v$ of incident light is as shown in the figure. The slope of the graph and intercept on $X$ -axis respectively are

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Answer: (b)

Einstein's equation: $KE = h\nu - \phi_0$ , a straight line $y = mx + c$ .
Slope $= h$ (Planck's constant).
At $KE = 0$ : $\nu = \phi_0/h = \nu_0$ , the threshold frequency.
So the answer is (b) Planck's constant, threshold frequency.

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