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MHT CET 2020 (19 Oct, Shift 2) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2020 (19 Oct, Shift 2)

Q55MHT CET 2020 · 19 OCT · SHIFT 2Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

The graph of stopping potential $V_s$ against frequency $v$ of incident radiation is plotted for two different metals $P$ and $Q$ as shown in the graph. $\phi_p$ and $\phi_Q$ are work-functions of $P$ and $Q$ respectively, then

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Answer: (b)

$eV_s = h\nu - \phi$ , so the intercept on the $\nu$ -axis is the threshold frequency $\nu_0 = \phi/h$ .
Line $P$ cuts the axis at a lower frequency than line $Q$ : $\nu_{0P} < \nu_{0Q}$ .
$\phi = h\nu_0 \Rightarrow \phi_P < \phi_Q$
So the answer is (b) $\phi_P < \phi_Q$ .

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