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MHT CET 2024 (3 May, Shift 2) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2024 (3 May, Shift 2)

Q33MHT CET 2024 · 3 MAY · SHIFT 2Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

The graph of stopping potential ' $\mathrm{V_s}$ ' against frequency ' $v$ ' of incident radiation is plotted for two different metals ' X ' and ' Y ' as shown in graph. ' $\phi_x$ ' and ' $\phi_y$ ' are work functions of ' $x$ ' and ' $Y$ ' respectively then

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Answer: (b)

$V_s = \dfrac{h}{e}(\nu - \nu_0)$ ; each line cuts the $\nu$ axis at its threshold frequency.
From the graph, X cuts at $\nu_0$ and Y at $\nu_0' > \nu_0$ .
$\phi = h\nu_0$ , so $\phi_x < \phi_y$ .
So the answer is (b).

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