The graph shows the variation of photocurrent with anode potential for four different radiations. Let Ia, Ib, Ic and Id are intensities and fa, fb, fc and fd be the frequencies for the curves a, b, c and d respectively, then (a) fb > fa, fb = fc, Ic = Id (b) fb = fa, fb > fc, Ic > Id (c) fb fc, Ic = Id

Answer: (a). Stopping potential (where the curve meets the axis) depends on frequency; saturation current depends on intensity. Stopping potential: a smallest, b and c equal, d largest, so fa fa, fb = fc, Ic = Id.

The graph shows the variation of photocurrent with anode potential… | MHT CET 2025 (26 Apr, Shift 2)

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs

The graph shows the variation of photocurrent with anode potential for four different radiations. Let $\mathrm{I_a}, \mathrm{I_b}, \mathrm{I_c}$ and $\mathrm{I_d}$ are intensities and $\mathrm{f_a}, \mathrm{f_b}, \mathrm{f_c}$ and $\mathrm{f_d}$ be the frequencies for the curves $\mathrm{a, b, c}$ and d respectively, then

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Answer: (a)

Stopping potential (where the curve meets the axis) depends on frequency; saturation current depends on intensity.
Stopping potential: $a$ smallest, $b$ and $c$ equal, $d$ largest, so $f_a < f_b = f_c < f_d$ .
Saturation: $c$ and $d$ reach the same level, so $I_c = I_d$ .
So the answer is (a) $f_b > f_a$ , $f_b = f_c$ , $I_c = I_d$ .

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2025 (26 Apr, Shift 2)

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