The graph shows the variation of voltage (v) across the plates of two parallel plate capacitos A and B versus increase of charge Q stored in them. Then (a) capacity of both capacitors is same. (b) capacity of A is higher than B. (c) capacity of B is higher than A. (d) capacity of both is zero.

Answer: (b). For a capacitor V = Q/C, so the slope of the V – Q line is 1/C. For the same Q, VA CB. So the answer is (b) capacity of A is higher than B.

The graph shows the variation of voltage (v) across the plates of two… | MHT CET 2025 (22 Apr, Shift 1)

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Capacitance of a Conductor

The graph shows the variation of voltage (v) across the plates of two parallel plate capacitos $A$ and $B$ versus increase of charge $Q$ stored in them. Then

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Answer: (b)

For a capacitor $V = \frac{Q}{C}$ , so the slope of the $V$ – $Q$ line is $\frac{1}{C}$ .
For the same $Q$ , $V_A < V_B$ , so line A has the smaller slope.
Smaller slope means larger capacitance: $C_A > C_B$ .
So the answer is (b) capacity of $A$ is higher than $B$ .

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