The graph which depicts the results of Rutherford gold foil experiment with α -particales is: θ: Scattering angle Y: Number of scattered α -particles detected (Plots are schematic and not to scale) (a) (b) (c) (d)

Answer: (c). N(θ) ∝ (1)/(sin ⁴(θ/2)), so most α -particles go nearly undeviated and very few are scattered through large angles. The curve is very high near θ = 0 and drops sharply, flattening out towards θ = π. So the answer is (c).

The graph which depicts the results of Rutherford gold foil… | JEE Main 2020 (8 Jan, Shift 1)

Q11JEE Main 2020 · 8 JAN · SHIFT 1Easy

Atomic Models & Alpha-Particle Scattering

The graph which depicts the results of Rutherford gold foil experiment with $\alpha$ -particales is: $\theta$ : Scattering angle

Y: Number of scattered $\alpha$ -particles detected (Plots are schematic and not to scale)

Show answer and solution

Answer: (c)

$N(\theta) \propto \dfrac{1}{\sin^4(\theta/2)}$ , so most $\alpha$ -particles go nearly undeviated and very few are scattered through large angles.
The curve is very high near $\theta = 0$ and drops sharply, flattening out towards $\theta = \pi$ .
So the answer is (c).

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