The graph which shows the variation of the de Broglie wavelength ( λ) of a particle and its associated momentum (p) is (a) (b) (c) (d)

Answer: (d). de Broglie relation: λ = h/p, so λ p = h = constant. λ ∝ 1/p gives a rectangular hyperbola, falling steeply and approaching the axes. So the answer is (d).

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Quantum Numbers, X-rays & Other Questions

The graph which shows the variation of the de Broglie wavelength ( $\lambda$ ) of a particle and its associated momentum (p) is

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Answer: (d)

de Broglie relation: $\lambda = \frac{h}{p}$ , so $\lambda p = h$ = constant.
$\lambda \propto \frac{1}{p}$ gives a rectangular hyperbola, falling steeply and approaching the axes.
So the answer is (d).

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