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JEE Main 2013 (25 Apr, Shift 1) · Gravitational Potential & Energy

Gravitational Potential & Energy question from JEE Main 2013 (25 Apr, Shift 1)

Q32JEE Main 2013 · 25 APR · SHIFT 1Medium

Gravitational Potential & Energy

The gravitational field in a region is given by: E⃗=(5 N/kg)i^+(12 N/kg)j^\vec{E} = (5\text{ N/kg})\hat{i} + (12\text{ N/kg})\hat{j}. If the potential at the origin is taken to be zero, then the ratio of the potential at the points (12 m, 0) and (0, 5 m) is:

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Answer: (b)

  1. V=−∫E⃗⋅dr⃗=−(5x+12y)V = -\int \vec{E}\cdot d\vec{r} = -(5x + 12y), with V(0,0)=0V(0,0) = 0.
  2. V(12,0)=−60 J/kgV(12,0) = -60\ \text{J/kg}, V(0,5)=−60 J/kgV(0,5) = -60\ \text{J/kg}
  3. Ratio =1= 1
  4. So the answer is (b) 1.
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