The gravitational pull of the moon is (1/6)th of the earth and mass of moon is (1/8) th of the earth. This implies that the (a) radius of moon is (1/4) th of the earth's radius. (b) radius of the earth is ( √(4/3)) th of the moon's radius. (c) moon's radius is half that of the earth. (d) radius of the earth is (4/3) th of the moon's radius.

Answer: (b). g = GM/R² ⇒ (gm)/(ge) = (Mm)/(Me)((Re)/(Rm))² 1/6 = 1/8((Re)/(Rm))² ⇒ ((Re)/(Rm))² = 4/3 So the answer is (b) Re = √(4/3) Rm.

The gravitational pull of the moon is (1/6)th of the earth and mass… | MHT CET 2025 (23 Apr, Shift 2)

Q20MHT CET 2025 · 23 APR · SHIFT 2Medium

Acceleration Due to Gravity

The gravitational pull of the moon is $\left(\frac{1}{6}\right)^{th}$ of the earth and mass of moon is $\left(\frac{1}{8}\right)$ th of the earth. This implies that the

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Answer: (b)

$g = \frac{GM}{R^2} \Rightarrow \frac{g_m}{g_e} = \frac{M_m}{M_e}\left(\frac{R_e}{R_m}\right)^2$
$\frac{1}{6} = \frac{1}{8}\left(\frac{R_e}{R_m}\right)^2 \Rightarrow \left(\frac{R_e}{R_m}\right)^2 = \frac{4}{3}$
So the answer is (b) $R_e = \sqrt{\frac{4}{3}}\,R_m$ .

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