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NEET 1991 (AIPMT) · Energy of the Electron & Energy Levels

Energy of the Electron & Energy Levels question from NEET 1991 (AIPMT)

Q61NEET 1991 · AIPMTEasy

Energy of the Electron & Energy Levels

The ground state energy of H-atom is 13.6 eV. The energy needed to ionize H-atom from its second excited state

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Answer: (a)

  1. Ground state energy is −13.6-13.6 eV (13.6 eV in magnitude).
  2. Second excited state is n=3n = 3: E3=−13.69=−1.51E_3 = \frac{-13.6}{9} = -1.51 eV.
  3. Energy needed to ionise =0−E3=1.51= 0 - E_3 = 1.51 eV
  4. So the answer is (a) 1.511.51 eV.
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