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MHT CET 2024 (9 May, Shift 1) · Other / Mixed: Atoms & Bohr Links

Other / Mixed: Atoms & Bohr Links question from MHT CET 2024 (9 May, Shift 1)

Q1MHT CET 2024 · 9 MAY · SHIFT 1Medium

Other / Mixed: Atoms & Bohr Links

The gyromagnetic ratio and Bohr magneton are given respectively by [Given $e =$ charge on electron, $m =$ mass of electron, $h =$ Planck's constant]

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Answer: (a)

Gyromagnetic ratio $= \frac{\mu}{L} = \frac{evr/2}{mvr} = \frac{e}{2m}$
Bohr magneton: $\mu_B = \frac{e}{2m} \cdot \frac{h}{2\pi} = \frac{eh}{4\pi m}$
So the answer is (a).

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