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Law of Radioactive Decay question from NEET 2013

Q97NEET 2013Easy

Law of Radioactive Decay

The half life of a radioactive isotope 'X' is 20 years. It decays to another element 'Y' which is stable. The two elements 'X' and 'Y' were found to be in the ratio 1: 7 in a sample of a given rock. The age of the rock is estimated to be

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Answer: (d)

  1. N0=NX+NYN_0 = N_X + N_Y, so NXN0=11+7=18=(12)3\frac{N_X}{N_0} = \frac{1}{1+7} = \frac{1}{8} = \left(\frac{1}{2}\right)^3.
  2. Age =3×20=60= 3\times20 = 60 years.
  3. So the answer is (d) 60 years.
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