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NEET 2000 (AIPMT) · Law of Radioactive Decay

Law of Radioactive Decay question from NEET 2000 (AIPMT)

Q119NEET 2000 · AIPMTEasy

Law of Radioactive Decay

The half-life of a radioactive material is $3\text{ h}$ . If the initial amount is $300\text{ g}$ , then after $18\text{ h}$ , it will remain

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Answer: (a)

$n = \frac{18}{3} = 6$ half-lives.
Remaining $= \frac{300}{2^6} = \frac{300}{64} = 4.6875\text{ g}$ .
So the answer is (a) $4.68\text{ g}$ .

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