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NEET 2020 (Phase 2) · Law of Radioactive Decay

Law of Radioactive Decay question from NEET 2020 (Phase 2)

Q75NEET 2020 · PHASE 2Medium

Law of Radioactive Decay

The half life of a radioactive sample undergoing α\alpha-decay is 1.4×1017 s1.4 \times 10^{17}\text{ s}. If the number of nuclei in the sample is 2.0×10212.0 \times 10^{21}, the activity of the sample is nearly

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Answer: (b)

  1. A=λN=0.693TNA = \lambda N = \frac{0.693}{T}N.
  2. A=0.693×2.0×10211.4×1017≈0.99×104A = \frac{0.693\times2.0\times10^{21}}{1.4\times10^{17}} \approx 0.99\times10^4 Bq.
  3. So the answer is (b) 10410^4 Bq.
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