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JEE Main 2024 (5 Apr, Shift 1) · P-V Diagrams & Cyclic Processes

P-V Diagrams & Cyclic Processes question from JEE Main 2024 (5 Apr, Shift 1)

Q36JEE Main 2024 · 5 APR · SHIFT 1Medium

P-V Diagrams & Cyclic Processes

The heat absorbed by a system in going through the given cyclic process is:

Figure

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Answer: (a)

  1. For a cycle ΔU=0\Delta U = 0, so heat absorbed = work = area enclosed.
  2. The circle spans 60 to 340 on both axes, so each semi-axis is 140 units: 140140 kPa and 140140 cc.
  3. Area =π(140×103)(140×10−6)=19.6π≈61.6= \pi (140 \times 10^{3})(140 \times 10^{-6}) = 19.6\pi \approx 61.6 J
  4. So the answer is (a) 61.6 J.
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