The height at which the weight of the body becomes (1/9) th its weight on the surface of earth is (R = radius of earth) (a) 8R (b) 4R (c) 3R (d) 2R

Answer: (d). (R/R+h)² = 1/9 R + h = 3R ⇒ h = 2R So the answer is (d) 2R.

The height at which the weight of the body becomes (1/9) th its… | MHT CET 2023 (12 May, Shift 1)

Q51MHT CET 2023 · 12 MAY · SHIFT 1Easy

Acceleration Due to Gravity

The height at which the weight of the body becomes $\left(\frac{1}{9}\right)$ th its weight on the surface of earth is $(R =$ radius of earth)

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Answer: (d)

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