The height at which the weight of the body becomes (1/16)th of its weight on the surface of the earth of radius ' R ' is (a) 2 R (b) 3 R (c) 4 R (d) 5 R

Answer: (b). Wh/W = (R/R+h)² = 1/16 R + h = 4R ⇒ h = 3R So the answer is (b) 3 R.

The height at which the weight of the body becomes (1/16)th of its… | MHT CET 2024 (3 May, Shift 2)

Q31MHT CET 2024 · 3 MAY · SHIFT 2Easy

Acceleration Due to Gravity

The height at which the weight of the body becomes $\left(\frac{1}{16}\right)^{\text{th}}$ of its weight on the surface of the earth of radius ' $R$ ' is

Show answer and solution

Answer: (b)

$\frac{W_h}{W} = \left(\frac{R}{R+h}\right)^2 = \frac{1}{16}$
$R + h = 4R \Rightarrow h = 3R$
So the answer is (b) 3 R.

Report a mistake

More questions on Acceleration Due to Gravity

The height above the earth's surface at which the acceleration due to gravity becomes…MHT CET 2024 (2 May, Shift 1)
A 90 kg body placed at 2R distance from surface of earth experiences gravitational pull…JEE Main 2024 (4 Apr, Shift 2)
The depth 'd' at which the value of acceleration due to gravity becomes 1/n-1 times the…MHT CET 2024 (11 May, Shift 1)
Assuming the earth to be a sphere of uniform mass density, a body weighed 300 N on the…JEE Main 2024 (6 Apr, Shift 2)
The height ' h ' from the surface of the earth at which the value of ' g ' will be…MHT CET 2024 (10 May, Shift 2)
An object of mass 100 kg falls from point A to B as shown in figure. The change in its…NEET 2024
If R is the radius of the earth and the acceleration due to gravity on the surface of…JEE Main 2024 (1 Feb, Shift 1)
A simple pendulum is placed at a place where its distance from the earth's surface is…JEE Main 2024 (30 Jan, Shift 2)

Acceleration Due to Gravity question from MHT CET 2024 (3 May, Shift 2)

More questions on Acceleration Due to Gravity