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MHT CET 2024 (10 May, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2024 (10 May, Shift 2)

Q36MHT CET 2024 · 10 MAY · SHIFT 2Medium

Acceleration Due to Gravity

The height ' h ' from the surface of the earth at which the value of ' gg ' will be reduced by 64%64\% than the value at surface of the earth is ( R=R = radius of the earth)

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Answer: (b)

  1. Reduced by 64%64\%: gh=0.36g=gR2(R+h)2g_h = 0.36g = g\frac{R^2}{(R+h)^2}.
  2. RR+h=0.6⇒R+h=5R3\frac{R}{R+h} = 0.6 \Rightarrow R + h = \frac{5R}{3}
  3. So the answer is (b) h=23Rh = \frac{2}{3}R.
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