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JEE Main 2026 (4 Apr, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2026 (4 Apr, Shift 2)

Q4JEE Main 2026 · 4 APR · SHIFT 2Easy

Acceleration Due to Gravity

The height in terms of radius of the earth (R)(R), at which the acceleration due to gravity becomes g9\frac{g}{9}, where gg is acceleration due to gravity on earth's surface, is

______.

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Answer: (c)

  1. (RR+h)2=19\left(\frac{R}{R+h}\right)^2 = \frac{1}{9}
  2. R+h=3R⇒h=2RR + h = 3R \Rightarrow h = 2R
  3. So the answer is (c) 2R2R.
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