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JEE Main 2022 (25 Jun, Shift 1) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2022 (25 Jun, Shift 1)

Q76JEE Main 2022 · 25 JUN · SHIFT 1Easy

Acceleration Due to Gravity

The height of any point P above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point P will be: (Given g = acceleration due to gravity at the surface of earth).

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Answer: (d)

$h = 2R$ (diameter), so the distance from the centre is $3R$ .
$g_P = g\left(\frac{R}{3R}\right)^2 = \frac{g}{9}$
So the answer is (d) g/9.

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