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JEE Main 2021 (27 Aug, Shift 2) · Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Calorimetry, Latent Heat & Mechanical Equivalent of Heat question from JEE Main 2021 (27 Aug, Shift 2)

Q27JEE Main 2021 · 27 AUG · SHIFT 2Easy

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

The height of Victoria falls is 63 m. What is the difference in temperature of water at the top and at the bottom of fall?

[Given 1 cal = 4.2 J and specific heat of water = 1 cal g−^{-}1 ∘C−^{\circ}\text{C}^{-}1]

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Answer: (a)

  1. mgh=mcΔT⇒ΔT=ghcmgh = mc\Delta T \Rightarrow \Delta T = \dfrac{gh}{c} with c=4200c = 4200 J/kg K.
  2. ΔT=9.8×634200≈0.147∘C\Delta T = \dfrac{9.8 \times 63}{4200} \approx 0.147^\circ\text{C}
  3. So the answer is (a).
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