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NEET 2012 (AIPMT, Prelims) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from NEET 2012 (AIPMT, Prelims)

Q31NEET 2012 · AIPMT · PRELIMSEasy

Time of Flight, Maximum Height & Range

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

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Answer: (b)

  1. RH=4tan⁡θ\frac{R}{H} = \frac{4}{\tan\theta}
  2. R=H⇒tan⁡θ=4R = H \Rightarrow \tan\theta = 4
  3. So the answer is (b) θ=tan⁡−1(4)\theta = \tan^{-1}(4).
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