Physics Circle home Student Login

Home›Chapters›Semiconductor Electronics PYQs›P-N Junction Diode›Question 62

JEE Main 2022 (26 Jun, Shift 1) · P-N Junction Diode

P-N Junction Diode question from JEE Main 2022 (26 Jun, Shift 1)

Q62JEE Main 2022 · 26 JUN · SHIFT 1Medium

P-N Junction Diode

The I-V characteristics of a p-n junction diode in forward bias is shown in the figure. The ratio of dynamic resistance, corresponding to forward bias voltage of 2 V and 4 V respectively, is:

Figure

Show answer and solution

Answer: (b)

  1. Dynamic resistance rd=ΔVΔIr_d = \dfrac{\Delta V}{\Delta I}, taken from the small segment of the curve near each voltage.
  2. Near 22 V: r1=2.1−2(10−5)×10−3=0.15×10−3=20 Ωr_1 = \dfrac{2.1 - 2}{(10 - 5)\times 10^{-3}} = \dfrac{0.1}{5\times 10^{-3}} = 20\ \Omega
  3. Near 44 V: r2=4.2−4(250−200)×10−3=0.250×10−3=4 Ωr_2 = \dfrac{4.2 - 4}{(250 - 200)\times 10^{-3}} = \dfrac{0.2}{50\times 10^{-3}} = 4\ \Omega
  4. r1:r2=20:4=5:1r_1 : r_2 = 20 : 4 = 5 : 1
  5. So the answer is (b) 5:15:1.
Report a mistake

More questions on P-N Junction Diode