The increase in pressure required to decrease the volume of a water sample by 0.2% is P × 10⁵ N m⁻². Bulk modulus of water is 2.15 × 10⁹ N m⁻². The value of P is _________. Numerical answer type. Work it out, then open the answer.

Answer: 43. Δ P = B(Δ V)/(V) Δ P = 2.15×10⁹×0.002 = 4.3×10⁶ = 43×10⁵ N m⁻² So P = 43.

The increase in pressure required to decrease the volume of a water… | JEE Main 2025 (24 Jan, Shift 2)

Q6JEE Main 2025 · 24 JAN · SHIFT 2Easy

Density, Compressibility & Pascal's Law

The increase in pressure required to decrease the volume of a water sample by $0.2\%$ is $P \times 10^{5}\text{ N m}^{-2}$ . Bulk modulus of water is $2.15 \times 10^{9}\text{ N m}^{-2}$ . The value of P is _________.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 43

$\Delta P = B\dfrac{\Delta V}{V}$
$\Delta P = 2.15\times10^9\times0.002 = 4.3\times10^6 = 43\times10^5\text{ N m}^{-2}$
So $P = 43$ .

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