The increase in the pressure required to decrease the volume ( Δ V) of water is 6.3 × 10⁷ N/m². The percentage decrease in the volume is ______. (Bulk modulus of water = 2.1 × 10⁹ N/m².) (a) 2 % (b) 3 % (c) 6 % (d) 4 %

Answer: (b). (Δ V)/(V) = (Δ P)/(B) (Δ V)/(V) = (6.3 × 10⁷)/(2.1 × 10⁹) = 0.03 = 3% So the answer is (b) 3%.

The increase in the pressure required to decrease the volume ( Δ V)… | JEE Main 2026 (4 Apr, Shift 1)

Q1JEE Main 2026 · 4 APR · SHIFT 1Easy

Bulk Modulus & Compressibility

The increase in the pressure required to decrease the volume ( $\Delta V$ ) of water is $6.3 \times 10^{7}\text{ N/m}^2$ . The percentage decrease in the volume is ______.

(Bulk modulus of water $= 2.1 \times 10^{9}\text{ N/m}^2$ .)

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Answer: (b)

$\dfrac{\Delta V}{V} = \dfrac{\Delta P}{B}$
$\dfrac{\Delta V}{V} = \dfrac{6.3 \times 10^7}{2.1 \times 10^9} = 0.03 = 3\%$
So the answer is (b) 3%.

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