The increase in the pressure required to decrease the volume ( Δ V) of water is 6.3 × 10⁷ N/m². The percentage decrease in the volume is ______. (Bulk modulus of water = 2.1 × 10⁹ N/m².) (a) 2 % (b) 3 % (c) 6 % (d) 4 %

Answer: (b). Bulk modulus: B = (Δ P)/(Δ V/V) ⇒ (Δ V)/(V) = (Δ P)/(B). (Δ V)/(V) = 6.3 × 10⁷2.1 × 10⁹ = 3 × 10⁻² So the answer is (b) 3%.

The increase in the pressure required to decrease the volume ( Δ V)… | JEE Main 2026 (4 Apr, Shift 1)

Q4JEE Main 2026 · 4 APR · SHIFT 1Medium

Density, Compressibility & Pascal's Law

The increase in the pressure required to decrease the volume ( $\Delta V$ ) of water is $6.3 \times 10^{7}\text{ N/m}^{2}$ . The percentage decrease in the volume is ______.

(Bulk modulus of water $= 2.1 \times 10^{9}\text{ N/m}^{2}$ .)

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Answer: (b)

Bulk modulus: $B = \dfrac{\Delta P}{\Delta V/V} \Rightarrow \dfrac{\Delta V}{V} = \dfrac{\Delta P}{B}$ .
$\dfrac{\Delta V}{V} = \dfrac{6.3 \times 10^{7}}{2.1 \times 10^{9}} = 3 \times 10^{-2}$
So the answer is (b) $3\%$ .

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