The initial average kinetic energy of the molecules was E, when a gas sample is at 27. When the gas is heated to 327, then the final average kinetic energy will be (a) √(2)E (b) 2 E (c) 300 E (d) 327 E

Answer: (b). Average KE ∝ T (kelvin). T₁ = 300 K, T₂ = 327 + 273 = 600 K E₂ = E × (600)/(300) = 2E So the answer is (b) 2E.

The initial average kinetic energy of the molecules was E, when a gas… | MHT CET 2025 (25 Apr, Shift 2)

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Pressure & Kinetic Energy of a Gas

The initial average kinetic energy of the molecules was E, when a gas sample is at $27^\circ\text{C}$ . When the gas is heated to $327^\circ\text{C}$ , then the final average kinetic energy will be

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Answer: (b)

Average KE $\propto T$ (kelvin).
$T_1 = 300$ K, $T_2 = 327 + 273 = 600$ K
$E_2 = E \times \frac{600}{300} = 2E$
So the answer is (b) 2E.

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