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JEE Main 2023 (13 Apr, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2023 (13 Apr, Shift 2)

Q142JEE Main 2023 · 13 APR · SHIFT 2Easy

Thermodynamic Processes

The initial pressure and volume of an ideal gas are P00 and V00. The final pressure of the gas when the gas is suddenly compressed to volume V04\frac{V_0}{4} will be:

(Given γ\gamma = ratio of specific heats at constant pressure and at constant volume)

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Answer: (d)

  1. Sudden compression has no time for heat exchange: adiabatic, PVγPV^{\gamma} = constant.
  2. P0V0γ=P(V04)γP_0V_0^{\gamma} = P\left(\frac{V_0}{4}\right)^{\gamma}
  3. P=P0(4)γP = P_0(4)^{\gamma}
  4. So the answer is (d) P0(4)γP_0(4)^{\gamma}.
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