Physics Circle home Student Login

Home›Chapters›Projectile Motion PYQs›Time of Flight, Maximum Height & Range›Question 28

JEE Main 2014 (11 Apr, Shift 1) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from JEE Main 2014 (11 Apr, Shift 1)

Q28JEE Main 2014 · 11 APR · SHIFT 1Medium

Time of Flight, Maximum Height & Range

The initial speed of a bullet fired from a rifle is 630 m/s. The rifle is fired at the center of a target 700 m away at the same level as the target. How far above the center of the target the rifle must be aimed in order to hit the target?

Show answer and solution

Answer: (c)

  1. Time to cover 700 m horizontally: t=700630=109 st = \frac{700}{630} = \frac{10}{9}\text{ s} (angle is tiny, so ux≈uu_x \approx u)
  2. Vertical drop in this time: h=12gt2=4.9×10081≈6.05 mh = \frac{1}{2}gt^2 = 4.9 \times \frac{100}{81} \approx 6.05\text{ m}
  3. Aim this much above the centre: about 6.1 m, answer (c).
Report a mistake

More questions on Time of Flight, Maximum Height & Range