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JEE Main 2023 (31 Jan, Shift 1) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from JEE Main 2023 (31 Jan, Shift 1)

Q16JEE Main 2023 · 31 JAN · SHIFT 1Medium

Time of Flight, Maximum Height & Range

The initial speed of a projectile fired from ground is uu. At the highest point during its motion, the speed of projectile is 32u\frac{\sqrt{3}}{2}u. The time of flight of the projectile is:

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Answer: (a)

  1. Speed at the top =ucos⁡θ=32u⇒θ=30∘= u\cos\theta = \frac{\sqrt{3}}{2}u \Rightarrow \theta = 30^\circ
  2. T=2usin⁡30∘g=ugT = \frac{2u\sin 30^\circ}{g} = \frac{u}{g}
  3. So the answer is (a) ug\frac{u}{g}.
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