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NEET 2015 (AIPMT) · Junction Transistor

Junction Transistor question from NEET 2015 (AIPMT)

Q101NEET 2015 · AIPMTMedium

Junction Transistor

The input signal given to a CE amplifier having a voltage gain of 150 is Vi = 2cos(15t + π3\frac{\pi}{3} ). The corresponding output signal will be

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Answer: (b)

  1. Output amplitude =AV×2=150×2=300= A_V \times 2 = 150 \times 2 = 300.
  2. A CE amplifier reverses phase, so add π\pi: π3+π=4π3\dfrac{\pi}{3} + \pi = \dfrac{4\pi}{3}.
  3. Vo=300cos⁡(15t+4π3)V_o = 300\cos\left(15t + \dfrac{4\pi}{3}\right)
  4. So the answer is (b).
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