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NEET 2012 (AIPMT, Mains) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from NEET 2012 (AIPMT, Mains)

Q72NEET 2012 · AIPMT · MAINSEasy

Power, Power Factor & Wattless Current

The instantaneous values of alternating current and voltage in a circuit are given as i=12i = \frac{1}{\sqrt{2}} sin (100 π\pit) ampere

e=12sin⁡(100πt+π3)e = \frac{1}{\sqrt{2}}\sin\left(100\pi t + \frac{\pi}{3}\right) Volt

The average power in watts consumed in the circuit is

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Answer: (d)

  1. P=e0i02cos⁡ϕP = \frac{e_0i_0}{2}\cos\phi with ϕ=π3\phi = \frac{\pi}{3}
  2. P=12×12×12×12P = \frac{1}{2}\times\frac{1}{\sqrt{2}}\times\frac{1}{\sqrt{2}}\times\frac{1}{2}
  3. P=18 WP = \frac{1}{8}\text{ W}
  4. So the answer is (d) 18\frac{1}{8}.
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