The internal energy of a diatomic molecule (air) in 4 m × 4 m × 3 m sized room at 10⁵ N/m ² atmospheric pressure will be x × 10⁶ J. The value of x is (a) 6 (b) 12 (c) 4 (d) 16

Answer: (b). For a diatomic gas U = 5/2nRT = 5/2PV. V = 4 × 4 × 3 = 48 m³ U = 5/2 × 10⁵ × 48 = 12 × 10⁶ J So the answer is (b) x = 12.

The internal energy of a diatomic molecule (air) in 4 m × 4 m × 3 m… | MHT CET 2026 (15 May, Shift 2)

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Degrees of Freedom & Internal Energy

The internal energy of a diatomic molecule (air) in $4\text{ m} \times 4\text{ m} \times 3\text{ m}$ sized room at $10^{5}$ N/m $^{2}$ atmospheric pressure will be $x \times 10^{6}$ J. The value of $x$ is

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Answer: (b)

For a diatomic gas $U = \frac{5}{2}nRT = \frac{5}{2}PV$ .
$V = 4 \times 4 \times 3 = 48\ \text{m}^3$
$U = \frac{5}{2} \times 10^5 \times 48 = 12 \times 10^6$ J
So the answer is (b) $x = 12$ .

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